Jamal Adams and the Seahawks have agreed to terms on a four-year extension worth $70 million, according to NFL Network's Ian Rapoport.
The deal will reportedly include $38 million guaranteed and will make him the highest-paid safety in the NFL. The contract could be worth as much as $72 million over the four years with team and individual performance bonuses, according to NFL Network's Mike Garafolo.
Adams, 25, was entering the last year of his rookie contract and was due to make $9.86 million this season under the fifth-year option.