Penn State will take on the home team in the first round of the 2019 Big Ten Tournament in Bloomington, Indiana.
Earning the 10th seed, the Nittany Lions will take on No. 7 Indiana for the second weekend in a row, Thursday at 4:30 p.m.
Last weekend, the two teams met, with the Hoosiers taking the series on Penn State's home turf, 2-1.
Penn State hasn’t seen the tournament since 2017 after its 9-41 season last year. The No. 12 Nittany Lions upset the No. 5 Nebraska Cornhuskers 5-0 in the first round, but fell to No.