Jaguars linebacker Telvin Smith was named the AFC Defensive Player of the Week on Wednesday.
The second-year veteran intercepted a pass and returned it 26 yards for a touchdown in a 34-31 win over Buffalo on Sunday at London's Wembley Stadium.
Smith also recorded a team-high nine tackles with two behind the line. In addition to his pick six, the former Florida State standout broke up two more passes.
Smith, a fifth-round pick in 2014, has now won the award twice in his career. He earned in last season in Week 7 in a win over Cleveland.