Darnell Savage, a first-round pick of the Green Bay Packers in 2019, is leaving Green Bay and will sign a three-year deal with the Jacksonville Jaguars, according to Ian Rapoport of NFL Network.
Savage was the 21st overall pick and the first defensive back selected in the 2019 draft. The Packers traded two fourth-round selections to move up from No. 30 and get him.
Savage went on to play five up and down seasons with the Packers. A member of the All-Rookie team in 2019, Savage broke out as a difference maker to end the 2020 season and looked like one of the NFL’s best young safeties entering 2021.