Noticing a trend, yet? For the third week in a row, a Buffalo Bills player has been awarded as an AFC player of the week - and this time, it was rookie defensive end Greg Rousseau.
Rousseau won the award for his part in stomping the Chiefs in a 38-20 victory. He had several impact plays in the win - a sack, a tackle for loss, five tackles, and the first interception of his career. Rousseau is the fifth Bills rookie to win a Player of the Week award, joining Cornelius Bennett, C.J. Spiller, Greg Bell, and Josh Allen.