After spending his first four seasons with the Detroit Lions, A’Shawn Robinson signed a two-year contract with the Los Angeles Rams on Wednesday.
News came via Tom Pelissero of NFL Network, as his deal is worth $17 million.
Robinson, a former defensive tackle at Alabama, was selected in the second-round (No. 46 overall) of the 2016 NFL Draft.
He posted 172 total tackles in 58 career games and had five sacks, three forced fumbles, three fumble recoveries, one interception and 16 breakups. The 6-foot-4, 330-pounder had 40 tackles (four for loss), 1.5 sacks, three breakups, one forced fumble and two fumble recoveries in 2019.